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Two short magnet A and B of magnetic dip...

Two short magnet `A` and `B` of magnetic dipole mement `M_(1)` and `M_(2)` respectively are placed as shown.The axis of `A` and the equatorial line of `B` are the same.Find the magnetic force on one magnet due to other.

Text Solution

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The correct Answer is:
1

`vec(tau)=vec(M)_(2)xxvec(B)_(1)`
`tau = M_(2)B_(1)sin 90^(@)`
`= 1 xx (mu_(0))/(4pi) (M_(1))/((1)^(3))`
` = 1 xx 10^(-7) `N.m
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