Home
Class 12
PHYSICS
In a potentiometer setup a cell of emf E...

In a potentiometer setup a cell of emf `E_1` is balanced by length 75cm. If the above cell is changed by another cell of emf `E_@`. (`E_1/E_2 = 3/2)` then find difference of balancing length

A

25

B

30

C

15

D

50

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS SECTION B|30 Videos
  • JEE MAIN 2023

    JEE MAINS PREVIOUS YEAR|Exercise Question|455 Videos

Similar Questions

Explore conceptually related problems

Figure shows a potentiometer circuit, a cell of emf E_1 is balanced by length l' of the potentiometer wire. If this cell is replaced by another of emf E_2 , it is found that total length of potentiometer wire has to be increased by 50%, in order to have the same balance length (l'). Then E_1//E_2 is______.

In a poteometer a cell of emf 1.5V gives a balanced point 32cm length of the cell is replaced by another cell then the balance point shifts to 65.0cm the emf of second cell is

In potentiometer experiment, a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, then balancing length is found to be 40 cm. What is the emf of second cell ?

In a potentiometer arragement , a cell of emf 1.5 V , gives a balance point at 30 cm length of the wire . If the give cell is replaced by another cell , the balance point shifts to 50 cm . What is the emf of the second cell ?

In a potentiometer arrangement, a cell of emf 1.5 V gives a balance point at 27 cm length of wire. If the cell is replaced by another cell and balance point shifts to 54 cm, the emf of the second cell is :

In a potentiometer a cell of emf 1.5 V gives a balanced point at 32 cm length of the wire. If the cell is replaced by another cell then the balance point shifts to 65 cm. Then the emf of second cell is

In a potentiometer arrangement a cell of emf 1.20 V given a balance point at 30 cm length of the wire. The cell a now replaced by another cell of unknown emf. The ratio of emfs of the two cells is 1.5 , calculate the difference in the balancing length of the potentiometer wire in the two cases

In a potentiometer arrangement a cell of emf 1.5 V gives a balance point at 30 cm length of wire. Now, when the cell is replaced by another celle , the balance point shifts to 50 cm. What is the emf of second cell ?

JEE MAINS PREVIOUS YEAR-JEE MAIN 2022-Question
  1. Two metals M1 and M2 of thermal conductivity k1 and K2 are joined end ...

    Text Solution

    |

  2. In a nuclear reaction U^220 to x^105 + y^115 binding energy per nucleo...

    Text Solution

    |

  3. In a potentiometer setup a cell of emf E1 is balanced by length 75cm. ...

    Text Solution

    |

  4. Two soap bubbles of radius r(1) and r(2) combine. Find radius of curva...

    Text Solution

    |

  5. Statement 1- In uniform magnetic field speed and energy of a charge pa...

    Text Solution

    |

  6. Find distance between first maxima in single slit diffraction pattern ...

    Text Solution

    |

  7. A scaled rod of length 1m is balanced at 40cm mark as shown in figure....

    Text Solution

    |

  8. A particle of mass 100g is in horizontal circular motion with the help...

    Text Solution

    |

  9. Work done by Carnot engine whose heat accepted 5000Kcal from 727^@C an...

    Text Solution

    |

  10. Same kinetic energy of proton, deuterium and alpha particle.Find the c...

    Text Solution

    |

  11. If the distance between sun and earth is 3R. Find time of revolution i...

    Text Solution

    |

  12. Charge on capacitor is increased by 2C nad energy stored becomes 144%....

    Text Solution

    |

  13. A string with mass m object on one end and rotate in a circle with uni...

    Text Solution

    |

  14. Heat given to system containing monoatomic gas is Q . Q/4 work done by...

    Text Solution

    |

  15. FInd IL

    Text Solution

    |

  16. Parallel plate capacitor charged to 60 mili C plate loses charge at 1....

    Text Solution

    |

  17. Ratio of Intensities are 9/4. Find ratio of maximum intensity and mini...

    Text Solution

    |

  18. A projectile fired at an angle 45^0 with horizontal. After 2s it acqui...

    Text Solution

    |

  19. 100 gram nail is being hit by hammer of 1.5 kg with a velocity of 60 m...

    Text Solution

    |

  20. A block of 5kg is thrown vertically upwards air resistance is constant...

    Text Solution

    |