Parallel plate capacitor charged to 60 mili C plate loses charge at `1.8x10^-8`. Calculate magnitude of displacement current

A parallel plate capacitor is charged. If the plates are pulled apart

A parallel plate capacitor is charged to 60 muC . Due to a radioactive source, the plate losses charge at the rate of 1.8 xx 10^(-8) Cs^(-1) . The magnitued of displacement current is

The charge of a parallel plate capacitor is varying as q = q0 sin omega t. Then find the magnitude of displacement current through the capacitor. (Plate Area = A, separation of plates = d)

Parallel Plate Capacitor |Energy Stored In A Charged Capacitor

A parallel plate capacitor of area 50cm^(2) and plate separation 3.0 mm is charged initially to 80 mu C . Due to radio-active source nearby , the medium between the plates gets slightly conducting and the plate loses charge the rate of 1.5 xx 10^(-8) "Cs"^(-1) . what is the magnitude and direction of displacement current ? What is the magnetic field between the plates

A parallel plate capacitor with circular plates of radius R is being charged as shown. At the instant shown, the displacement current in the region between the plates enclosed between ( R)/(2) and R is given by

The voltage between the plates of a parallel-plate capacitor of capacitance 1.0 mu F is changing at the rate of 5 "Vs"^(-1) . What is the displacement current in the capacitor?

A parallel plate condenser of capacity 10 muF is charged with a constant charging current of 0.16 A . The displacement current is

The voltage between the plates of a parallel plate capacitor of capacitance 1 muF is changing at the rate of 8 V/s. What is the displacement current in the capacitor?