If , K= Kinetic energy of H-atom
P= potential energy of H-atom
T= total energy of H-atom
as the total energy increses then which if the following option is correct ?

Options

A. K & P increses but T decreses
B. T & P increses but K decreses
C. None of above
D. all Increase

Answer

To solve the problem, we need to analyze the relationship between kinetic energy (K), potential energy (P), and total energy (T) of a hydrogen atom.

### Step-by-step Solution:

1. **Understanding Total Energy**:
The total energy (T) of the hydrogen atom is given by the equation:
\[ T = K + P \]
where \( K \) is the kinetic energy and \( P \) is the potential energy.

2. **Relationship Between Kinetic and Potential Energy**:
For a hydrogen atom, it is known that:
\[ T = -\frac{K}{2} \]
and
\[ P = 2T \]
This means that the potential energy is twice the total energy.

3. **Considering the Increase in Total Energy**:
If we say that the total energy \( T \) is increasing, we can denote this as:
\[ \Delta T > 0 \]
Since \( T \) is negative for a bound system like the hydrogen atom, an increase in total energy means that \( T \) is becoming less negative (moving towards zero).

4. **Effect on Potential Energy**:
From the relationship \( P = 2T \), if \( T \) increases, then:
\[ P = 2T \quad \text{(increases as T increases)} \]
Thus, the potential energy \( P \) also increases.

5. **Effect on Kinetic Energy**:
Since \( T = K + P \) and \( P \) is increasing, we need to analyze the kinetic energy. Given that \( T \) is increasing (becoming less negative), and knowing that:
\[ K = T - P \]
If \( P \) increases while \( T \) increases, the kinetic energy \( K \) must decrease because the total energy is still constrained by the relationship \( T = K + P \).

6. **Conclusion**:
Therefore, if the total energy \( T \) increases, we conclude that:
- The potential energy \( P \) increases.
- The kinetic energy \( K \) decreases.

### Final Answer:
As the total energy increases, the correct options are:
- Potential energy increases.
- Kinetic energy decreases.