`(x-1)/3=(y-2)/2=(z-1)/lamda`
`(x-2)/4=(y-lamda)/1=(z-4)/3`
If the shortest distance between the lines is `2sqrt3` then sum of all possible values of `6lamda` will be

(x-lamda)/2=(y-2)/1=(z-1)/1 "and"(x-sqrt3)/1=(y-1)/(-2)=(z-2)/1 If the shortest distance between the above two lines is 1 then sum of possible values of lamda .

if given (x-1)/2=(y+1)/4=(z-1)/3 & (2x-1)/5=(y-2)/3=z/6 then the shortest length between two lines is

The shortest distance between the line 1+x=2y=-12z and x=y+2=6z-6 is

The shortest distance between the lines 2x+y+z-1=0=3x+y+2z-2 and x=y=z, is

The shortest distance between the lines x=y+2 = 6z-6 and x + 1 = 2y = - 12z is

If the shortest distance between the lines (x-4)/(1)=(y+1)/(2)=(z)/(-3) and (x-lambda)/(2)=(y+1)/(4)=(z-2)/(-5) is 6/sqrt5 then the sum of all possible values of lamda is

Shortest distance between line 2x+3y+4z-4=0=x+y+2z-3 and z-axis is -

If the lines (x-2)/(1)=(y-3)/(1)=(z-4)/(lamda) and (x-1)/(lamda)=(y-4)/(2)=(z-5)/(1) intersect then

Statement 1: The shortest distance between the lines x/2=y/(-1)=z/2 and (x-1)/(-2)=(y-1)/-2=(z-1)/4 is sqrt(2) . Statement 2: The shortest distance between two parallel lines is the perpendicular distance from any point on one of the lines to the other line.