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y=tan^-1(sec x^3-tan x^3) and pi/2 lt x^...

`y=tan^-1(sec x^3-tan x^3) and pi/2 lt x^3 lt (3pi)/2` then which of the following is correct

A

`xy''+2y'=0`

B

`x^2y''-6y+(3pi)/2=0`

C

`x^2y''-6y+3pi=0`

D

`xy''-4y=0`

Text Solution

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The correct Answer is:
B
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