If `veca and vecb` are unit vector and angle between them is `theta` , find the relation between `abs(veca+vecb) and abs(veca-vecb)`

If veca and vecb are two vectors and angle between them is theta , then

If veca and vecb are two unit vectors and the angle between them is 60^(@) then ((1+veca.vecb))/((1-veca.vecb)) is

If veca and vecb are unit vector and theta is the angle between then, then |(veca - vecb)/2| is:

veca*vecb=abs(vecaxxvecb) then abs(veca-vecb) is

The angle between vector (vecA) and (vecA-vecB) is :

If veca and vecb are two vectors of magnitude 1 inclined at 120^(@) , then find the angle between vecb and vecb-veca .

Consider three vectors veca, vecb and vecc . Vectors veca and vecb are unit vectors having an angle theta between them For vector veca, |veca|^2=veca.veca If veca_|_vecb and veca_|_vecc then veca||vecbxxvecc If veca||vecb, then veca=tvecb Now answer the following question: The value of sin(theta/2) is (A) 1/2 |veca-vecb| (B) 1/2|veca+vecb| (C) |veca-vecb| (D) |veca+vecb|

If veca and vecb are unit vectors inclined at an angle theta , then the value of |veca-vecb| is

If veca and vecb are two unit vectors and theta is the angle between them, then the unit vector along the angular bisector of veca and vecb will be given by