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Consider P1 :~(p to ~q) and P2:(p wedge ...

Consider `P_1 :~(p to ~q)` and `P_2:(p wedge ~q) wedge ((~p) vvq)`
If `p to ((~p)vvq)` is false then

A

`P_1` is true ,`P_2` is false

B

`P_1` is false,`P_2` is true

C

Both `P_1` and `P_2` are true

D

Both `P_1` and `P_2` are false

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