If physical quantities A,B,C and D are related as follows `(A^2 B^3)/C^4 = D`, then the magnitude of the maximum value of percentage error in D is

In an experiment, the percentage of error occurred in the in the measurement of physical quantities A,B,C and D are 1%, 2%,3% and 4% respectively. Then the maximum percentage of error in the measurement X, where X=(A^(2)B^(1//2))/(C^(1//3)D^(3)) , will be

In the measurement of a physical quantity X = (A^(2)B)/(C^(1//3)D^(3)) . The percentage errors introduced in the measurement of the quantites A,B,C and D are 1%, 3% , 4% and 5% respectively . Then the minimum amount of percenatage of error in the measurment of X is contributed by

In the measurement of a physical quantity X = (A^(2) B)/(C^(1//3) D^(3)) . The percentage erros introduced in the measurments of the quantities A,B,C and D are 2%,2%,4% and 5% respectively. Then the minimum amount of percentage of error in the meaurement fo X is contributed by

A physical quantity P is given by P=(A^(3)B^((1)/(2)))/(C^(-4)D^((3)/(2)) The quantity which brings in the maximum percentage error in P is,(Fractional error in A,B,C and D are equal

A physical quantity x is calculated from x = ab^(2)//sqrt(c ) . Calculate the percentage error in measuring x when the percentage errors in measuring a , b , and c are 4 , 2 , and 3%, respectively .

A physical quantity A is related to four observable a,b,c and d as follows, A=(a^2b^3)/(csqrtd) , the percentage errors of measurement is a,b,c and d,are 1% , 3% , 2% and 2% respectively. What is the percentage error in the quantity A?

A physical quantity X is related to four measurable quantities a,b,c and d as follows X=a^2b^3c^((5)/(2))d^-2 . The percentage error in the measurement of a,b,c and d are 1%,2%,3% and 4% repectively. What is the percentage erroe in quantity X? If the value of X calculated on the basis of the above relation is 2.763, to what value should you round off the result.