If Q is the mirror image of `P(-1,0,-1)` with respect to plane `x+y+z=5` and a line parallel to PQ passes through `A(1,-1,-1)` intersect given plane at a point R , then value of `QR^2` is

the mirror image of point (3,1,7) with respect to the plane x-y+z=3 is P .then equation plane which is passes through the point P and contains the line (x)/(1)=(y)/(2)=(z)/(1)

Consider the line L given by the equation (x -3)/(2) = ( y-1)/( 1) = ( z -2)/(1). Let Q be the mirror image of the point (2,3 –1) with respect to L. Let a plane P be such that it passes through Q, and the line L is perpendicular to P. Then which of the following points is one the plane P?

The plane through the intersection of the planes x+y+z=1 and 2x+3y-z+4=0 and parallel to Y-axis also passes through the point

Let P be the image of the point (3, 1, 7) with respect to the plane x-y+z=3 . The equation of the plane passing through P and parallel to x-2y+3z=7 is

Find the image of the point (p, q, r) with respect to the plane 2x+ y + z = 6. Hence find the image of the line (x-1)/2=(y-2)/1=(z-3)/4 with respect to the plane.

If the image of the point P(1,-2,3) in the plane 2x+3y-4z+22= (measured parallel to the line with dr's is 1,4,5 is Q ,then PQ is

A horizontal plane 4x-3y+7z=0 is given. Find a line of greatest slope passes through the point (2,1,1) in the plane 2x+y-5z=0

A plane P = 0 passing through the point (1, 1, 1) is perpendicular to the planes 2x-y+2z=5 and 3x+6y-2z=7 . If the distance of the point (1, 2, 3) from the plane P = 0 is k units, then the value of 34k^(2) is equal to

Find the equation of the plane which is parallel to the plane 2x-3y+z+8=0 and which passes through the point (-1,1,2).

Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0