If R is the radius and A is the mass number, then log R versus log A graph will be

The graph between log k versus 1//T is a straight line.

If A is mass number of a nucleus of Radius R, then

In the above question, the curve between log I and log R will be :

Atomic nucleus is central core of every atom in which the whole of positive charge and almost entire mass of atom is concentrated. It is a tiny sphere of a radius R is given by R=R_(o)A^(1//3) , where R_(o)=1.4xx10^(-15)m , a constant and A the mass number of nucleus A graph between 'log((R )/(R_(0))) , and 'logA'

Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot of log""(x)/m versus log p is shown in the graph. x/m is proportional to:

The intercept on Y - axis in the graph of log (x)/(m) versus log P gives

In an adsorption experiment a graph between log x/m versus log P was fond to be linear with a slope of 45^@) . The intercept on the log x/m axis was found to 0.70 . Calculate the amount of gas adsorbed per gram of charcoal under a pressure of 1 atm [log5=0.70]