A solid `A_xB_y` has ccp structure A forms ccp and B is present in all the octahedral voids if atoms A are removed from two opposite faces then x will be ?

Oxygen atom forms FCC unit cell with 'A ' atoms occupying all tetrahedral voids and 'B ' atoms occupying all octahedral voids. If atoms are removed from two of the body diagonals then determine the formula of resultant compound formed .

In a hypothetical solid C atoms form C C P lattice with A atoms occupying all the Tetrahedral Voids and B atoms occupying all the octahedral voids A and B atoms are of the appropriate size such that there is no distortions in the CCP lattice. Now if a plane is cut ( as shown ) then the section would like

If a solid 'AB','A' atoms have ccp arrangement and B atoms occupy all the octahedral sites. If all the face centred atoms along one of the axes are removed, then what will be the resultant stoichiometry of the compound?

In a crystalline solid, atom of A form fcc packing and atoms of B occupy all octahedral voids. If all the atoms along one body diagonal are removed then what will be the simplest formula of the crystalline solid ?

Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids , while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is :

Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

In a solid AB, A atoms have a ccp arrangement and B atoms occupy all the octahedral sites. If all the face-centred atoms along one of the axes passing through body centres are removed, then what will be the resultant stoichiometry of compound ?