Home
Class 12
CHEMISTRY
In an electrochemical cell Find Delta G^...

In an electrochemical cell Find `Delta G^@` if `E_(A^(2+)/A)^o=-0.33V, E_(B/B^(2+))^o=0.50V`.

A

-0.20F

B

-0.34F

C

-0.02F

D

-0.04F

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise Chemistry (Section B)|10 Videos
  • JEE MAIN 2023

    JEE MAINS PREVIOUS YEAR|Exercise Question|455 Videos

Similar Questions

Explore conceptually related problems

The two half cell reaction of an electrochemical cell is given as Ag^(+)+e^(-)rarrAg ,E_(Ag^(+))^(@)=-0.3995 V Fe^(2+)rarrFe^(3+)+e^(-),E_(Fe^(3+))^(@)//Fe^(2+)=-0.7120V The value of cell EMF will be

The standard cell potential for the electrochemical cell Af//Af^+ || AgI//Ag, E_(AfI(s)//Ag)^0 =- 0.151 V , E_(Ag^+//Ag)^@ = 0.799V .

For the electrochemical cell, M|M^(+) ||X^(-)|X , E_(M^(+)//M)^(@) = 0.44 V and E_(X//X^(-))^(@) = 0.33 V . From this data we can deduce that :

For the electrochemical cell (M|M^(+))|| (X^(-)|X) E^(@) (M^(+)//M) = 0.44V and E^(@) (X//X^(-))=0.33V From this data one can deduce that :

An electrochemical cell has two half cell reaction as, A^(2+)+2e^-,E^0=0.34V XtoX^(2+)+2e^-,E^0=+2.37V . The cell voltage will be

Two half-reactions of an electrochemical cell are given below : MnO_(4)^(-)(aq)+8H^(+)(aq)+5e^(-) toMn^(2+)(aq)+4H_(2)O(l), E^(@)=+1.51" V" Sn^(2+)(aq) to Sn^(4+)(aq)+2e^(-),E^(@)=-0.15" V"