Force on a charge between plates of capacitor is 10N. What will be force if one plate is removed.

A capacitor is given a charge q . The distance between the plates of the capacitor is d . One of the plates is fixed and the other plate is moved away from the other till the distance between them becomes 2d . Find the work done by the external force.

The potentials of the two plates of capacitor are +10V and -10 V . The charge on one of the plate is 40 C . The capacitance of the capacitor is

What is the nature of the charge on the plates of capacitor ?

Force of attraction between the plates of a parallel plate capacitor is

A parallel plate capcitor of capacitance C is charged to a potential V by a battery. Without disconencting the battery = distance between the plates of capacitor is triple and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ? (a) Capacitance of capacitor (b) Charge on capacitor (c ) Energy density of capacitor.

The separation between the plates of a charged parallel-plate capacitor is increased. The force between the plates

separation between the plates of a parallel-plate capacitor is 2 mm and the area of its plates is 5cm^(2) . If the capacitor is charged such that it has 0.01J energy stored in it, the electrostatic force of attraction between its plates is _______N.

A battery is used to charge a parallel plate capacitor till the potential differece between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

Between the plates of a parallel plate capacitor a dielectric plate in introduced just to fill the complete space between the plates. The capacitor is charged and later disconnected from the battery. The dielectric plate is then slowly drawn out of the capacitor plates. the plot of the potential difference across the plates and the length of the dielectric plate drawn out is