In an experiment of potentiometer, if R= 8 ohm then null point AC is equal to 3 m and where R= 4 ohm, then AC is 2 m. find the value of internal resistance r.

A potentiometer circuit with potentiometer wire 10 m long, and an ideal main battery of e.m.f 8 V, has been set up for finding the internal resistance of a given cell. When the resistance R, connected across the given cell, has values of (i) infinity, (ii) 10 omega , the balancing lengths, on the potentiometer wire are found to be 2.4 m and x respectively. If the internal resistance of the cell is 2 omega, the value of x is

In the given potentiometer circuit length of the wire AB is 3 m and resistance is R = 4.5 Omega . The length AC for no deflection in galvanometer is

In an experiment with potentiometer to measure the internal resistance of a cell when the cell is shunted by 5Omega the null point is obtained at 2m .When the cell is shunted by 10Omega the null point is obtained at 3m .The internal resistance of the cell is

A potentiometer circuit has been setup for finding. The internal resistance of a given cell. The main battery used a negligible internal resistance. The potentiometer wire itsefl is 4 m long. When the resistance, R , connected across the given cell, has value of (i) Infinity 9.5 Omega , (ii) the 'balancing length' , on the potentiometer wire are found to be 3 m and 2.85 m , respectively. The value of internal resistance of the cell is

In an experiment of meter bridge, a null point is obtaining at the center of the bridge wire. When a resistance of 10 ohm is connected in one gap, the value of resistance other gap is

Find power in entire circuit where internal resistance is 0.6 ohm.