Home
Class 12
CHEMISTRY
Correct Statement about Pcl5 is (a) PC...

Correct Statement about `Pcl_5` is
(a) `PCl_5` has Trigonal Bipyramidal geometry
(b) Axial bonds are stronger than equatorial bonds
(c) All equatorial bonds are in the same plane
(d) `Pcl_5` Shows `sp^3`d hybridization

A

A,b and C

B

A,b and D

C

A,c and D

D

B,c and D

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • JEE MAIN 2021

    JEE MAINS PREVIOUS YEAR|Exercise Chemistry (Section B)|10 Videos

  • JEE MAIN 2023

    JEE MAINS PREVIOUS YEAR|Exercise Question|455 Videos

Similar Questions

Explore conceptually related problems

How many equitorial bonds are there are in PCl_(5) ?

Assertion : In trigonal bipyramidal structure two axial bonds are longer than the equatorial bonds. Reason : Axial bonds suffer more repulsion as compared to equatorial bonds.

Statement-1 : PCl_(5) has trigonal bipyramidal shape . and Statement-2 : Length of all P-Cl bonds in PCl_(5) is equal

Describe hybridisation in the case of PCl_(5) and SF_(6) The axial bonds are longer as compared to equatorial bonds in PCl_(5) whereas in SF_(6) both axial bonds and equatorial bonds and have the same bond length. Explain.

PCl_5 has trigonal pyramidal geometry with sp^3 d hybridisation in gases and liquid state but in solid state it exist as ionic compound. In presence of small amount of water, PCl_5 hydrolysis to form.

PCl_5 has trigonal pyramidal geometry with sp^3 d hybridisation in gases and liquid state but in solid state it exist as ionic compound. In crystalline state PCl_5 exists as.

Describe the hybridisation in case of PCl_(2). Why are the axial bonds longer as compared to equatorial bonds ?

PCl_5 has trigonal pyramidal geometry with sp^3 d hybridisation in gases and liquid state but in solid state it exist as ionic compound. The hyridisation of P and shape of POCl_3 are.