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If f(x)+f(x+k)=n and I1=int0^(4k) f(x) d...

If `f(x)+f(x+k)=n and I_1=int_0^(4k) f(x) dx and I_2=int_-k^(3k) f(x) dx` then `I_1+I_2` equals

A

`nk`

B

`2nk`

C

`3nk`

D

`4nk`

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