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a0=a1=0 , a(n+2)=2a(n+1)-an+1 , n ge 0 t...

`a_0=a_1=0 , a_(n+2)=2a_(n+1)-a_n+1 , n ge 0` then `sum_(n=2)^oo a_n/7^n` is equal to

A

`21/16`

B

`7/216`

C

`49/216`

D

`16/49`

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JEE MAINS PREVIOUS YEAR-JEE MAIN 2022-Question
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