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Given activation Energy for a chemical r...

Given activation Energy for a chemical reaction is 23566 J . Initial temprature in 310K and final temprature is 300K if the rate constant of the reaction in initial and final condition is `K_1` and `K_2` respectively and the value of `K_2/K_1` is `x xx 10^(-3)` Find the value of x. [Given , log(0.75) = -0.13]

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