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In the figure, an ideal flows through the tube, which is of uniform cross-section. The liquid has velocities v_A and v_B and pressures p_A and p_B at points A and B respectively. (i) v_A = v_B (ii) v_B gt v_A ltbr gt (iii) p_A = p_B (iv) p_B gt p_A . .

In uniform electric field E=10 N//C , find a. V_A-V_B , b. VB-V_C

1 mu C charge is shifted from A to B, and it is found that work done by an external force is 40 mu J . In doing so against electrostatic forces, find potential difference V_A - V_B .

In a certain region, electric field E exists along the x - axis which is uniform. Given B = 2 sqrt(3) m and BC = 4 m . Points A, B, and C are in x y plane. . Find the potential difference V_A - V_B between the points A and B .

An electric field is expressed as vec E = 2 hat i + 3 hat j . Find the potential difference (V_A - V_B) between two points A and B whose position vectors are given by r_A = hat i + 2 hat j and r_B = 2 hat i + hat j + 3 hat k .

Find out the following a. V_A - V_B b. V_B - V_C c. V_C - V_A d. V_D - V_C e. V_A - V_D f. Arrange the order of potential for points (A, B,C and D). .

The potential difference V_A - V_B for the circuit shown in fig. is. -(22//x)V. find the value of x.

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