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For a first order reaction K = 6.3 xx 10...

For a first order reaction K = `6.3 xx 10^(-18)``e^(-2600/T)` then the value of activation energy in KJ is

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The activation energy of a first order reaction at 300 K is kJ mol^(-1) . In the presence of a catalyst, the activation energy gets lowered to 50kJ mol^(-1) at 300 K . How many times the reaction rate change in the presence of a catalyst at the same temperature ?

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The substance undergoes first order decomposition.The decomposition follows two parallel first order reactons as : K_1=10^(-2) sec^(-1) and K_2=10^(-2)sec^(-1) If the corresponding activation energies of parallel reaction are 100 and 120 kJ "mol"^(-1) then the net activation energy of A is/are:

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On introducing a ctatlyst at 500 K, the rate of a first order reaction increases by 1.718 times. The activation energy in the presence of a catalyst is 60.5 kJ "mol"^(-1) . The slop of the plot of In k (sec^(-1)) against 1/T in the absence of catalyst is :

On introfucing a catalyst at 500K , the rate of a first order reaction increases by 1.718 times. The activation energy in the presence of a catalyst is 4.15 KJ mol^(-1) . The slope of the polt of k(s^(-1)) against 1//T in the absence of catalyst is

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