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Figure below shows a body of mass M movi...

Figure below shows a body of mass `M` moving with the uniform speed on a circular path of radius, `R`. What is the change in acceleration in going from `P_(1)` to `P_(2)`

A

Zero

B

`v^(2)//2R`

C

`2v^(2)//R`

D

`(v^(2))/(R) xx sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta a= 2a sin ((theta)/(2))=2a xx sin 45^(@)= sqrt2a= sqrt2 (v^(2))/(R)`
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