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A sphere of mass 10 kg and radius 0.5 m ...

A sphere of mass 10 kg and radius 0.5 m rotates about a tangent. The moment of inertia of the solid sphere about tangent is

A

`5kg - m^(2)`

B

`2.7 kg - m^(2)`

C

`3.5 kg - m^(2)`

D

`4.5 kg - m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I= I_(CM) + MR^(2)= (2)/(5) MR^(2) + MR^(2)= (7)/(5) MR^(2)`
`I= (7)/(5) xx 10 xx (0.5)^(2)= 3.5 kg- m^(2)`
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