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The diameter of a thin circular disc of ...

The diameter of a thin circular disc of mass 2 kg is 0.2 m. Its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc is

A

`0.01`

B

`0.03`

C

`0.02`

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
`I= (MR^(2))/(2) + MR^(2)= (3)/(2) MR^(2)`
`= (3)/(2) xx 2 xx (0.1)^(2)= 0.03 kg-m^(2)`
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