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The diameter of a thin circular disc of ...

The diameter of a thin circular disc of mass 2 kg is 0.2 m. Its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc is

A

`0.01`

B

`0.03`

C

`0.02`

D

3

Text Solution

Verified by Experts

The correct Answer is:
B
`I= (MR^(2))/(2) + MR^(2)= (3)/(2) MR^(2)`
`= (3)/(2) xx 2 xx (0.1)^(2)= 0.03 kg-m^(2)`
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Knowledge Check

  • A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc (in kg m^(2) )

    A
    0.01
    B
    0.03
    C
    0.02
    D
    3

  • Four similar point masses (m each) are symmetrically placed on the circumference of a disc of mass M and radius R. Moment of inertia of the system about an axis passing through centre O and perpendicular to the plane of the disc will be

    A
    `MR^(2)+4mR^(2)`
    B
    `MR^(2)+(8)/(5)mR^(2)`
    C
    `mR^(2)+4MR^(2)`
    D
    `(MR^(2))/(2)+4mR^(2)`

  • A uniform disc of mass 5 kg has a radius of 0.5 m. Its moment of inertia about an axis passing through a point on its circumference and perpendicular to its plane is

    A
    `"1.25 kg - m"^(2)`
    B
    `"0.5 kg - m"^(2)`
    C
    `"4 kg - m"^(2)`
    D
    `"1.875 kg - m"^(2)`