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The moment of inertia of a sphere of mas...

The moment of inertia of a sphere of mass M and radius R about an axis passing through its centre is `(2)/(5) MR^(2)` . The radius of gyration of the sphere about a parallel axis to the above and tangent to the sphere is

A

`(7)/(5)R`

B

`(3)/(5)R`

C

`(sqrt((7)/(5)))R`

D

`(sqrt((3)/(5)))R`

Text Solution

Verified by Experts

The correct Answer is:
C

MOI about tangent `I= I_(CM)+ MR^(2)= (2)/(5) MR^(2) + MR^(2)= (7)/(5) MR^(2)`
Now, `(7)/(5) MR^(2)= MK^(2) rArr K= sqrt((7)/(5))R`
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