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The radius of gyration of a disc of mass...

The radius of gyration of a disc of mass 50 g and radius 2.5 cm, about an axis passing through its centre of gravity and perpendicular to the plane is

A

0.52cm

B

1.76cm

C

3.54cm

D

6.54cm

Text Solution

Verified by Experts

The correct Answer is:
B
`I= (MR^(2))/(2)= (0.05 xx (2.5 xx 10^(-2))^(2))/(2)`
Now `I= MK^(2)`
`rArr (0.05 xx (2.5 xx 10^(-2))^(2))/(2)= MK^(2)`
`rArr K= (2.5)/(sqrt2)cm= 1.76cm`
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