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A rod of length L and mass M is bent to ...

A rod of length L and mass M is bent to form a semi-circular ring as shown in figure. The moment of inertia about XY is

A

`(ML^(2))/(2pi^(2))`

B

`(ML^(2))/(pi^(2))`

C

`(ML^(2))/(4pi^(2))`

D

`(2ML^(2))/(pi^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`I= (MR^(2))/(2), pi R= L rArr R= (L)/(pi)`
`rArr I= (ML^(2))/(2pi^(2))`
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