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The radius of gyration of a solid shaper...

The radius of gyration of a solid shapere of radius r about a certain axis is r. The distance of this axis from the centre of the shpere is

A

r

B

0.5r

C

`sqrt0.6 r`

D

`sqrt0.4 r`

Text Solution

Verified by Experts

The correct Answer is:
C
k=r
`I= mr^(2) = (2)/(5) mr^(2) + md^(2)`
`rArr r^(2)- (2)/(5) r^(2)= d^(2) rArr d^(2)= (3r^(2))/(5)`
`rArr d= sqrt0.6 r`
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