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The moment of inertia of a solid disc ma...

The moment of inertia of a solid disc made of thin metal of radius R and mass M about one of its diameters is given by `(MR^(2))/(4)` . What will be the moment of inertia about this axis if the disc is folded in half about this diameter .

A

`(MR^(2))/(8)`

B

`(MR^(2))/(2)`

C

`(MR^(2))/(4)`

D

`MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Moment of inertia will remain same.
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