Home
Class 11
PHYSICS
What constant force, tangential to the e...

What constant force, tangential to the equator should be applied to the earth to stop its rotation in one day

A

`1.3 xx 10^(22) N`

B

`8.26 xx 10^(28) N`

C

`1.3 xx 10^(23)N`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`omega_(0)= 2pi` rad/day, `omega= 0`
`alpha= (0- 2pi)/(t) = 2pi "rad/day"^(2)= (2pi)/((86400)^(2)) "rad"//s^(2)`
Torque required to stop the earth
`tau= I alpha= FR`
`rArr F= (I alpha)/(R)= ((2)/(5) MR^(2) xx alpha)/(R)= (2)/(5) MR xx alpha`
`= (2)/(5) xx 6 xx 10^(24) xx 6400 xx 10^(3) xx (2pi)/((86400)^(2))`
= `1.3 xx 10^(22) N`
Promotional Banner

Similar Questions

Explore conceptually related problems

If earth stops rotating

[" The magnitude of the constant tangential force "],[" to be applied to the equator to stop the rotation "],[" of earth in one day,"in N" ) is "],[(2)/(5)MR alpha],[(1)/(3)MR alpha],[" MR "alpha],[(7)/(3)MR alpha]

Earth completes one rotation in

A disc has mass 'M' and radius 'R'. How much tangential force should be applied to the rim of the disc, so as to rotate with angular velocity 'omega' in time 't' ?

A disc has mass 'M" and radius 'R'. How much tangential force should be applied to the rim of the disc so as to rotate with angular velocity omega in time 't'?

If R is the radius of the earth and w is angular velocity with which it rotates about its axis the variation in the value of g at 45^(@) latitude of the earth stops its rotation will be

A point starts from rest and moves along a circular path with a constant tangential acceleration. After one rotation, the ratio of its radial acceleration to its tangential acceleration will be equal to

A car moves with a constant speed toward East. A force is applied on the car to make it stop. The direction of the applied force is toward