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A particle of mass m is moving in yz-pla...

A particle of mass `m` is moving in yz-plane with a unifrom velocity `v` with its trajectory running parallel to +ve y-axis and intersecting z-axis at `z = a` Fig. The change in its angular momentum about the origin as it bounces elastically from a wall at y = constant is :

A

`mv a hat(e)_(x)`

B

`2mv a hat(e)_(x)`

C

`ymv hat(e)_(x)`

D

`2y mv hat(e)_(x)`

Text Solution

Verified by Experts

The correct Answer is:
B
The initial velocity is `v_(1)= v hat(e)_(y)` and after reflection from the wall, the final velocity is `v_(f)= - v hat(e)_(y)`. The trajectory is described as position vector `vec(r)= y hat(e)_(y) + a hat(e)_(z)` Hence, the change in angular momentum is `vec(r) xx m (v_(f)- v_(j))= 2 mv a hat(e)_(x)`
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