Home
Class 11
PHYSICS
A particle of mass m is moving in a circ...

A particle of mass m is moving in a circular orbit of radius r in a force field given by `vec(F)=-(K)/(r^(2))hat(r)` . The angular momentum L of the particle about the centre varies as

A

`L prop sqrtr`

B

`L prop r^(3//2)`

C

`L prop (1)/(sqrtr)`

D

`L prop r^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(mv^(2))/(r)= (K)/(r^(2)) rArr v= sqrt((K)/(mr))`
`L= mvr = sqrt(mrK)` Thus we get `L prop sqrtr`
Promotional Banner

Similar Questions

Explore conceptually related problems

IF a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-(K)/(r^(2))) , then its total energy is

A particle of mass m is describing a circular path of radius r with uniform speed. If L is the angular momentum of the particle (about the axis of the circle), then the kinetic energy of the particle is given by

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (-1//r^(2)) , the total energy is

A satellite of mass m is revolving in a circular orbit of radius r. The relation between the angular momentum J of satellite and mass m of earth will be -

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle of mass m is moving on a circular path of radius r with uniform speed v , rate of change of linear momentum is

A particle of mass m is moving along a circle of radius r with a time period T . Its angular momentum is

A particle of mass 'm' is moving on a circular path of radius 'r' with uniform speed 'v'. Rate of change of linear momentum is

A particle is moving in a horizontal circular motion of radius R with constant speed v, then the angular momentum of particle about the axis passing through centre is....

A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-K//r^(2)) , where k is a constant. The total energy of the particle is -