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The total kinetic energy of a body of ma...

The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity of 2 m/s without slipping is 32.8 joule. The radius of gyration of the body is

A

0.25m

B

0.2m

C

0.5m

D

0.4m

Text Solution

Verified by Experts

The correct Answer is:
D
Total `K.E. = (1)/(2) mv^(2) (1+ (K^(2))/(R^(2)))= 32.8`
`rArr (1)/(2) xx 10 xx (2)^(2) [1+ (K^(2))/((0.5)^(2))] = 32.8`
`rArr K= 0.4m`
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