A rigid body of mass m rotates with the angular velocity __ about an axis at a distance 'a' from the centre of mass G. The radius of gyration about G is K. Then kinetic energy of rotation of the body about new parallel axis is

Options

A. `(1)/(2) mK^(2) omega^(2)`
B. `(1)/(2) ma^(2) omega^(2)`
C. `(1)/(2) m(a^(2) + K^(2)) omega^(2)`
D. `(1)/(2) m(a + K^(2)) omega^(2)`

Answer

C

Explanation

`I= mK^(2) + ma^(2)`
`K_(R)= (1)/(2) m (K^(2) + a^(2)) omega^(2)`