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Uniform ring of radius R is moving on a ...

Uniform ring of radius R is moving on a horizontal surface with speed v and then climbs up a ramp of inclination `30^(@)` to a height h. There is no slipping in the entire motion. Then h is

A

`v^(2)//2g`

B

`v^(2)//g`

C

`3v^(2)//2g`

D

`2v^(2)//g`

Text Solution

Verified by Experts

The correct Answer is:
B
`mgh= (1)/(2) mv^(2) + (1)/(2) mR^(2) ((v^(2))/(R^(2))) = mv^(2) rArr h= (v^(2))/(g)`
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