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Three particles of massses 50 g, 100 g a...

Three particles of massses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1m ( as shown in the figure ) . The ( x, y) coordinates of the centre of mass will be :

A

`((7)/(12)m,(sqrt(3))/(4)m)`

B

`((7)/(12)m,(sqrt(3))/(8)m)`

C

`((sqrt(3))/(4)m,(5)/(12)m)`

D

`((sqrt(3))/(8)m,(7)/(12)m)`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(cm)=(50xx0+100xx1+150xx1//2)/(50+100+150)`
= `(175)/(300)=(7)/(12)m`
`y_(cm)=(50xx0+100xx0+150sqrt(3)//2)/(300)=(sqrt(3))/(4)m`
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