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A solid sphere of mass M, radius R and h...

A solid sphere of mass `M`, radius `R` and having moment of inertia about as axis passing through the centre of mass as `I`, is recast into a disc of thickness `t`, whose moment of inertia about an axis passing through its edge and perpendicular to its plance remains `I`. Then, radius of the disc will be.

A

`(2R)/(sqrt(15))`

B

`Rsqrt((2)/(15))`

C

`(4R)/(sqrt(15))`

D

`(R)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(2)/(5)MR^(2)=(3)/(2)Mr^(2)`
implies `r=sqrt((4)/(15)R^(2))=(2)/(sqrt(15))R`
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