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Form a circular disc of radius R and ...

Form a circular disc of radius R and mass 9M , a small disc of mass M and radius R/3 is removed concentrically . The moment of inertia of the remaining disc about an axis perpendicular to the the plane of the disc and passing its centre is :-

A

`10MR^(2)`

B

`(37)/(9)MR^(2)`

C

`4MR^(2)`

D

`(40)/(9)MR^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I=((9M)R^(2))/(2)-[(M((R)/(3))^(2))/(2)+M((2R)/(3))^(2)]`
`I=4MR^(2)`
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