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The magnitude of torque on a particle of...

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the orifgin.If the force acting it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):

A

`(pi)/(6)`

B

`(pi)/(4)`

C

`(pi)/(8)`

D

`(pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

`vectau=vecrxxvecF`
`vectau=rFsintheta`
`2.5=5xx1xxsinthetaimpliestheta=30^(@)impliestheta=pi//6`.
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