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Moment of inertia of a body about a give...

Moment of inertia of a body about a given axis is `1.5 kg m^(2)`. Initially the body is at rest. In order to produce a rotational kinetic energy of 1200 J, the angular acceleration of `20 rad//s^(2)` must be applied about the axis for a duration of _________ (in sec).

A

2s

B

`2.5` s

C

5 s

D

3s

Text Solution

Verified by Experts

The correct Answer is:
A
From `omega=omega_(0)+alpha t`
we get, `omega=20 t`
Rotational `KEimplies (1)/(2)I omega^(2)=1200` J
`(1)/(2)(105)(20t)^(2)=1200`
`t^(2)=4implies t=2 "sec"`
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