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A thin rod of mass 0.9 kg and length ...

A thin rod of mass 0.9 kg and length 1 m is suspended , at rest form one end so that it can freely oscillate in the vertical plane. A particle of move 0.1 kg moving in a striaght line with velcoity 80 n/s hits the rod at is bottom most point and sticks to it (see figure) . The angluar speed ( in rad/s) of the rod immediately after the collision will be .

Text Solution

Verified by Experts

The correct Answer is:
20
`S`
`vec(L_(i))=vec(L_(f))`
mvL = I omega
`mvL=((ML^(2))/(3)+mL^(2))omega`
`0.1xx80xx1=((0.9xx1^(2))/(3)+0.1xx1^(2))omega`
`8=((3)/(10)+(1)/(10))omega`
`8=(4)/(10)omega`
`omega=20 "rad/s"`
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