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Consider a uniform cubical box of side a...


Consider a uniform cubical box of side a on a rough floor that is to be moved by applying minimum possible force F at a point b above its centre of mass (see figure). It the coefficient of friction is `mu=0.4`, the maximum possible value of `100xx(b)/(a)` for box not to topple before moving is __________.

Text Solution

Verified by Experts

The correct Answer is:
50
For not toppling
`F((a)/(2)+b)le"mg"(a)/(2)`
`mu(a)/(2)+muble(a)/(2)`
`[ f=mu mg ]`
`0.2a+0.4ble0.5a`
`0.4ble0.3a`
`ble(3a)/(4)`
`ble0.75a` (in limiting case )
But it is not possible as maximum value of b can be equal to `0.5` a only
:. `(100(b)/(a))_("max")=50`
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