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An air bubble of volume 1.0 cm^(3) rises...

An air bubble of volume `1.0 cm^(3)` rises from the bottom of a lake 40 m deep at a temperature of `12^(@) C`. To what volume does it grow when it reaches the surface, which is at a temperature of `35^(@) C`. ? Given `1 atm = 1.01 xx 10^(5) Pa`.

A

5.4 `cm^3`

B

4.9 `cm^3`

C

2.0 `cm^3`

D

10.0 `cm^3`

Text Solution

Verified by Experts

The correct Answer is:
A
`(PV)/T="constant"rArr(P_1V_1)/T_1=(P_2V_2)/T_2`
`rArr((P+rhogh))/(273+12)=(PV_2)/(273+35)`
So, `V_2=5.4cm^3`
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