Home
Class 11
PHYSICS
A balloon contains 1500 m^(3) of helium ...

A balloon contains `1500 m^(3)` of helium at `27^(@)C` and 4 atmospheric pressue. The volume of helium at `-3^(@)C`temprature and 2 atmospheric pressure will be

A

500 `m^3`

B

700 `m^3`

C

900 `m^3`

D

1000 `m^3`

Text Solution

Verified by Experts

The correct Answer is:
C
`(PV)/T="constant"=(P_1V_1)/T_1=(P_2V_2)/T_2`
`rArrV_2=(P_1V_1)/T_1xxT_2/P_2=(1xx500)/(300)xx(270)/(0.5)rArrV_2=900m^3`
Promotional Banner

Similar Questions

Explore conceptually related problems

A balloon contains 1500 m^(3) of helium at 27^(@)C and 4 atmospheric pressue. The volume of helium at -3^(@)C themperature and 2 atmospheric pressure will be

A balloon contains 500m^(3) of He at 27^(@)C and 1 atm pressure. Then , the volume of He at -3^(@)C and 0.5 atm pressure will be

A partially inflated balloon contains 500 m^3 of helium at 27^@ C and 1 atm pressure. What is the volume of the helium at an altitude of 18000 ft , where the pressure is 0.5 atm and the temperature is -3^@ C ?

If the volume of air at 0^(@)C and 10 atmospheric pressure is 10 litre . Its volume, in litre, at normal temperature and pressure would be

The rms speed of helium gas at 27^(@)C and 1 atm pressure is 900 ms^(-1) . Then the rms speed of helium molecules at temperature 27^(@)C and 2 atm pressure is

The internal energy of one geam of helium at 100 K and one atmospheric pressure is

The volume of a gas at 27^(@)C and 760 mm atmospheric pressure is 500 c.c. what will be the volume of the gas at 27^(@)C and 380 mm of mercury pressure?