Home
Class 11
PHYSICS
Three containes of the same volume conta...

Three containes of the same volume contain three different gases. The masses of the molecules are `m_(1), m_(2)` and `m_(3)` and the number of molecules in their respective containers are `N_(1), N_(2)` and `N_(3)`. The gas pressure in the containers are `P_(1), P_(2)` and `P_(3)` respectively. All the gases are now mixed and put in one of the containers. The pressure `P` of mixture will be

A

`Plt(P_1+P_2+P_3)`

B

`P=(P_1+P_2+P_3)/3`

C

`P=P_1+P_2+P_3`

D

`Pgt(P_1+P_2+P_3)`

Text Solution

Verified by Experts

The correct Answer is:
C
Dalton.s law of partial pressure `P=P_1+P_2+P_3`
Promotional Banner

Similar Questions

Explore conceptually related problems

Two perfect gases at absolute temperature T_(1) and T_(2) are mixed. There is no loss of energy. The masses of the molecules are m_(1) and m_(2) . The number of molecules in the gases are n_(1) and n_(2) . The temperature of the mixture is

Three perfect gases at absolute temperature T_(1), T_(2) and T_(3) are mixed. The masses f molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no loss of energy, the final temperature of the mixture is

If N_(1), N_(2), N_(3) ………Are the number of molecules with molecular masses M_(1), M_(2), M_(3) …….respectively, then average molecular mass is expressed as

If three unreactive gases having partial pressures , P_(A) , P_(B) and P_(C) and their moles are 1 , 2 and 3 respectively then their total pressure will be

The ratio of pressure of the same gas in two containers in (n_(1) T_(1))/(n_(2) T_(2)) where n_(1) & n_(2) are the number of moles and T_(1) & T_(2) are respective temperatures. If the containers are now joined find the ratio of pressure to the pressure :