Home
Class 11
PHYSICS
The r.m.s sped of the molecules of a gas...

The r.m.s sped of the molecules of a gas at a pressure `10^5` Pa and temperature `0^@C` is 0.5km `sec^(-1)`. If the pressure is kept constant but temperature is raised to `819^@C`, the velocity will become

A

1.5 `kms^(-1)`

B

2 `kms^(-1)`

C

5 `kms^(-1)`

D

1 `kms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`v_(rms) prop sqrt(T) implies ((v_(rms))_1)/((v_(rms))_2)=sqrt((T_1)/(T_2))`
`implies (v_(rms))_2=500sqrt((1092)/(273))=1000 m // s = 1 km // sec`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A certain amount of a gas at 27^(@)C and 1 bar pressure occupies a volume of 25 m^(3) . If the pressure is kept constant and the temperature is raised to 77^(@)C what will be the volume of the gas?

The temperature of a gas at pressure P and volume V is 27^(@) C . Keeping its volume constant if its temperature is raised to 927^(@) C , then its pressure will be

The r.m.s speed of the molecules of an ideal gas Is V_0 If pressure of the gas is halved but temperature is kept constant then r.m.s. speed of the gas molecule will be

The temperature of a gas at pressure P and volume V is 27^(@)C . Keeping its volume constant. If its temperature is raised to 927^(@)C , then its pressure will be

If the rms speed of gas molecules is x cm s^(-1) at a pressure of p atmospheres, then the rms speed at a pressure of 2p atmospheres and constant temperature will be

The density of a gas at 27^(@)C and 1 atm is d. At what temperature would its density be 0.75d, if the pressure is kept constant?