If the oxygen `(O_2)` has root mean square velocity of C `ms^(-1)` then root mean square velocity of the hydrogen `(H_2)` will be

Options

A. C `ms^(-1)`
B. `1/Cms^(-1)`
C. `4Cms^(-1)`
D. `C/4ms^(-1)`

Answer

C

Explanation

`v_(rms) prop (1)/(sqrtM) implies (v_(O_2))/(v_(H_2))=sqrt(((M_(H_2))/(M_(O_2)))`
`implies (C)/(v_(H_2))=sqrt((2)/(32))=1/4`
`implies `v_(H_2)=4 " cm"//s`.