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The rms speed of oxygen molecules in a g...

The rms speed of oxygen molecules in a gas is `v`. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become

A

v

B

`sqrt(2v)`

C

2v

D

4v

Text Solution

Verified by Experts

The correct Answer is:
C
`v_(rms) prop sqrt((T)/(M)) implies ((v_(rms)_(O_2))/(v_(rms)_(O))) = sqrt(T/M xx (M//2)/(2T))`
`implies (v_(rms))_O=2(v_(rms))_(O_2)=2v`
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