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The temperature of the mixture of one mo...

The temperature of the mixture of one mole of helium and one mole of hydrogen is increased from 0°C to 100°C at constant pressure. The amount of heat delivered will be

A

600 cal

B

1200 cal

C

1800 cal

D

3600 cal

Text Solution

Verified by Experts

The correct Answer is:
B
`(C_p)_("mix")=(n_1C_(p_1)+n_2C_(p_2))/(n_1+n_2)`
`=(1xx5/2 R +1 xx 7/2 R)/(1+1)=3R=6 cal//mol^(-1)k^(-1)`
Heat `(DeltaQ)_P=nC_P DeltaT=2xx6xx100=1200` cal.
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