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10 moles of an ideal monoatomic gas at 1...

10 moles of an ideal monoatomic gas at `10^(@)C` are mixed with 20 moles of another monoatomic gas at `20^(@)C`. Then the temp. of the mixture is

A

`15.5^@C`

B

`15^@C`

C

`16^@C`

D

`16.6^@C`

Text Solution

Verified by Experts

The correct Answer is:
D
Principle of calorimeter
`n_1C_VDeltaT_1=n_2 C_V DeltaT_2`
`implies 10 xx (T - 10)=20(20-T)`
`implies T=16.6^@C`
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